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- What is the value of ΔG°cell? - Socratic
ΔG_text (cell)^@= "-332 kJ·mol"^"-1"" Your standard reduction potentials for each half-reaction are: ulbb ("Standard Reduction Potentials"color (white) (mmmmmll)E
- What are the spectator ions in the reaction between sodium . . . - Socratic
The nitrate and the natrium ions Na_2CO_3(aq) + 2AgNO_3(aq) rarr Ag_2CO_3(s)darr + 2NaNO_3(aq) The net ionic equation is: 2Ag^(+) + CO_3^(2-) rarr Ag_2CO_3(s)darr
- What is the formula of magnesium hydroxide? | Socratic
Mg (OH)_2 Now we know that hydroxides are salts of HO^-, and some metal ion Now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, and the atomic number of the metal is equal to 12 We look on the Periodic Table, and we find that Z=12, for "magnesium metal" As a Group 2 metal, magnesium forms a Mg^ (2+) ion, and hence its hydroxide is Mg (OH)_2
- What is the chemical formula for lithium hydroxide? - Socratic
Lithium is a Group 1 metal and commonly forms a M + ion Hydroxide anion, −OH, has a unit negative charge When they make music together, there is thus 1:1 stoichiometry between ions: Li(s) + H 2O(l) → LiOH (aq) + 1 2 H 2(g) ↑ ⏐ ⏐⏐
- 0. 10 moles of sodium cyanate dissolved in 250cm^3 distilled . . . - Socratic
The cyanate anions will react with water to form isocyanic acid, HNCO, and hydroxide anions, OH− This tells you that you can expect the pH of the resulting solution to be higher than 7 Calculate the molarity of the sodium cyanate solution by using the given number of moles and volume Keep in mind that you need to use liters of solution and
- Could a buffered solution be made by mixing aqueous . . . - Socratic
Could a buffered solution be made by mixing aqueous solutions of HCl and NaOH? Explain Why isn't a mixture of a strong acid and its conjugate base considered a buffered solution?
- What makes for a good leaving group? + Example - Socratic
A good leaving group has to be able to part with its electrons easily enough, so typically, it must be a strong acid or weak base relative to other substituents on the same molecule It helps to know the pKa of what would be leaving Let's say you had a mechanism where you are trying to do an E2 reaction to make an -OH (hydroxyl) group leave Maybe you have this compound on hand, sec-butanol
- Question #22e51 - Socratic
See the answer below; Having; Cu (OH)_2 + HCl -> ? Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water But; Cu (OH)_2 + HCl
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